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Автор - gagarin3288

Найдите множество корней уравнения а) (2x+3)^2-49=0

Ответ

Автор - angelovaanastasia24

Ответ:

(2x+3)²-49=0

(2x-4)×(2x+10)=0

(x-2)×(x+5)=0

x1=-5 x2=2

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