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Ответ

Ответ дан
IrkaShevko

Ответ:

Пошаговое объяснение:

306. y' = 3ˣ * ln3

307. f'(x) = 3x² + 2ˣ * ln2

308. f'(x) = 3^(sinx) * ln3 * cosx - 2²ˣ⁺¹ * ln2 + 2x

309. y' = 2^(sin5x) * ln2 * 5cos5x

310. f'(x) = 3^(sin²x) * ln3 * 2sinxcosx

311. y' = a³ˣ * 3lna

пользуемся формулами:

(xⁿ)' = nxⁿ⁻¹

(aˣ)' = aˣ * lna

f(g(x))' = f'(g(x)) * g'(x)

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