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Автор - 078108vv

1.Найдите корни уравнения
a)y(3y+7)=0
2.Решите уравнения
a)9y-y^2=0
b)x^3-x^2=0

Ответ

Автор - selmash21
1а.
у1=0
3у+7=0
3у=-7
у=-7/3=-2 1/3

2а.
у(9-у)=0
у1=0
9-у=0
у2=9

2б.
х^2(х-1)=0
х1=0
х-1=0
х2=1

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