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Автор - kristushon

Помогите решить
(y+3)/(4y(y-3))-(y-3)/(4y(y+3))

Ответ

Автор - Ваsилиsа
 frac{(y+3)}{4y(y-3)} +  frac{(y-3)}{4y(y+3)} =  frac{(y+3)(y+3) - ((y-3)(y-3))}{4y(y-3)(y+3)} +  frac{ y^{2}+3y+3y+9 - (y^{2}-3y-3y+9) }{[tex] frac{y^{2}+3y+3y+9 - y^{2}+3y+3y-9}{4y(y-3)(y+3)} =  frac{12y}{4y(y-3)(y+3)} =  frac{3}{y^{2}-9} }= 

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