Автор - cr1xme

Помогите.
Найдите sin a, если cos a= frac{-5}{13}   П<a<3П/2

Ответ

Автор - yellok
sin²a+cos²x=1
sina= sqrt{1-co s^{2}a } = sqrt{1- ( frac{-5}{13})^{2}  } = sqrt{1- frac{25}{169} } =  sqrt{frac{144}  {169} } = frac{12}{13}

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