Ответ Автор - natyak 2sin4xcos2x=1/2 tg2x4sin2xcos²2x=1/2*sin2x/cos2x8sinxcosxcos²2x=sinxcosx/cos2x8sinxcosxcos³2x-sinxcosx=0sinxcosx(8cos³2x-1)=0sinx=0 cosx=0 cos³2x=1/8x1=πn x2=π/2+πk cos2x=∛1/8 cos2x=1/2 2x=+-π/3+πp x3=+-π/6+πp/2n, k, p∈Z