Ответ Автор - Nullpo201 sin²x = 1-cos2x/21-cos2x = 1+cosxcosx+cos2x = 02cos3x/2•cosx/2 = 01)cos3x/2 = 03x/2 = π/2 + πkx = π/3 + 2πk/3k€Z2)cos x/2x/2 = π/2 + πnx = π+2πnn€Z