Всю первую строку , найти молекуляркую массу и омегу

Ответ:

Объяснение:

Mr(H2S) = 1*2 + 32 = 34

W(H) = Ar(H) *n / Mr(H2S)  *100% = 1*2 / 34  *100% =6%

W(S) = Ar(S) *n / Mr(H2S)  *100% = 32 *1 / 34  *100% = 94%

Mr(CS2) = 12 + 32*2 =76

W(C) = Ar(C) *n / Mr(CS2)  *100% = 12*1 / 76  *100% =16%

W(S) = Ar(S) *n / Mr(CS2)  *100% = 32*2 / 76  *100% = 84%

Mr(CaSO4) = 40 + 32+16*4 =136

W(Ca) = Ar(Ca) *n / Mr(CaSO4)  *100% = 40*1 / 136  *100% =29%

W(S) = Ar(S) *n / Mr(CaSO4)  *100% = 32*1 / 136  *100% = 23%

W(O) = Ar(O) *n / Mr(CaSO4)  *100% = 16*4 / 136  *100% =48%

Mr(Na2SO4) = 23*2 + 32 + 16*4 =142

W(Na) = Ar(Na) *n / Mr(Na2SO4)  *100% = 23*2 / 142  *100% =32%

W(S) = Ar(S) *n / Mr(Na2SO4)  *100% = 32*1 / 142  *100% = 22%

W(O) = Ar(O) *n / Mr(Na2SO4)  *100% = 16*4 / 142  *100% = 46%

Mr(Fe2(SO4)3 = 56*2 + 32*3 + 16*12 = 342

W(Fe) = Ar(Fe) *n / Mr(Fe2(SO4)3  *100% = 56*2 / 342  *100% =33%

W(S) = Ar(S) *n / Mr(Fe2(SO4)3  *100% = 32*3 / 342  *100% =28%

W(O) = Ar(O) *n / Mr(Fe2(SO4)3)  *100% = 16*4 / 342  *100% = 39%