Автор - asavushkin1

(х -7)(x+3) + (х-1)(x+5) + 26-0​

Ответ

Автор - veronica21032004

(x-7)(x+3) +(x-1)(x+5) + 26 = 0

x2 + 3x - 7x - 21 + x2 + 5x - x - 5 +26 = 0

2x2 = 0

x = 0

(x2 это х в квадрате)

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