ПОМОГИТЕ!!решите неравенство (x-3)^2<√5(x-3)

(x-3)^2 = sqrt 5 * (x-3)
x^2 - 6x + 9 = sqrt5*x - sqrt5 *3
x^2 - (6+sqrt5)x + 3(3+sqrt5)=0
x=((6+sqrt5)+-sqrt((6+sqrt5)^2 - 4* 3(3+sqrt5)))/2=
(6+sqrt5+-sqrt5)/2
x1=3;
x2=3+sqrt5