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Автор - exampel

система уравнений 2x^2+2xy+y^2=1 , 2x+y=1

Ответ

Автор - ARENMEHRABYAN
y=1-2x

2x^2+2x(1-2x)+(1-2x)^2=1
2x^2+2x-4x^2+1-4x+4x^2-1=0
2x^2-2x=0
2x(x-1)=0
x=0  или  x-1=0
               x=1

x=0   y=1-2*0=1

x=1   y=1-2*1=1-2=-1


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