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Автор - diasakparov

Помогите !!!!!!!!!!!!!!!!!!!!!!!!

Ответ

Автор - CVita
 left { {{x^2+y^2=25} atop {x+y=7}} right.  \  \ x=7-y \  \ (7-y)^2+y^2=25 \ 49-14y+y^2+y^2=25 \ 2y^2-14y+24=0 \ y^2-7y+12=0 \ D=b^2-4ac=1 \ y_1_,_2= frac{-b^+_- sqrt{D} }{2a} \ y_1=3 \ y_2=4 \  \ x_1=7-3=4 \ x_2=7-4=3

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