Автор - Pomogitesds

Решите систему уравнений-
X-y=4
X^2 + 2xy+ y^2=4

Ответ

Автор - 140599
х=4+у

(4+у)^2+2*(4+y)*y+y^2-4=0
16+8у+у^2+8у+2y^2+y^2-4=0
4y^2+16y+12=0
D=256-4*12*4=64
x1=-16+8/8=-1
x2=-16-8/8=-3

y1=-1-4=-5
y2=-3-1=-4

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