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Автор - kate32

найдите значение выражения (3x+)(9x^2-12x+16)-64-3(3x-1)(3x+1)+x^2 при х=1

Ответ

Автор - Alexandr130398
ты пропустил(а) цифру в начале: (3х+)?
раскрываем скобки и приводим подобные слагаемые:
27х^3-36x^2+48x+36x^2-48x+64-64-9x+3+x^2=27x^3+x^2-9x+3
подставляем х=1: 27+1-9+3=22

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