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Автор - razbitayakukla

Даны 4 целых числа, записанные в двоичной системе:
10101011 2, 11001100 2, 11000111 2, 11110100 2.
Сколько среди них чисел, меньших, чем BC16 +20 8

Ответ

Автор - saypl
10101011₂= 171
11001100
₂ = 204
11000111
= 199
11110100
₂= 244
BC₁₆ = 188
20₈ = 16
188+16 = 204
171<204
199<204
Ответ: 2 числа

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