Ответ Автор - m11m cos² (π-α) + cos² (3π/2 -α) =11) cos(π-α)=-cos(-α)=-cosα2) cos(3π/2-α)= cos(π+(π/2-α))=-cos(π/2-α)=-(-sin(-α))=-sinα3) (-cosα)² + (-sinα)²=cos²α+sin²α=1