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Автор - vika0427

Найти экстремумы функции: z=3 x^{2} + y^{2} -2xy+4x+2
пожалуйста помогите

Ответ

Автор - julyap
то что я смогла сделать 

z=3 x^{2} +y ^{2} -2xy+4x+2\z= x^{2} +y ^{2} -2xy+2 x^{2} +4x+2\z=(x-y) ^{2} +2( x^{2} +2x+1)\z=(x-y) ^{2} +2(x+2) ^{2}

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