Автор - liliyadytcheva

3 х в квадрате -7х-6=0

Ответ

Автор - krugly1981
3x² - 7x - 6 = 0
D = b² - 4ac
D = ( - 7)² - 4 × 3 × ( - 6) = 49 + 72 = 121 = 11²
x₁ = 7 + 11/ 2 × 3 = 18/ 6 = 3
x₂ = 7 - 11/ 2 × 3 = - 4/ 6 = - 2/3

Ответ: x₁ = 3, x₂ = - 2/3

Ответ

Автор - kazimierz2015
3x^2-7x-6=0 \ Delta=b^2-4ac=(-7)^2-4*3*(-6)=49+72=121=11^2 \ <br />
 sqrt{Delta}= sqrt{11^2}=11 \ <br />
x_1= frac{-b- sqrt{Delta} }{2a}= frac{7-11}{6}= frac{-4}{6}=- frac{2}{3}    \ <br />
x_2= frac{-b+ sqrt{Delta} }{2a}= frac{7+11}{6}= frac{18}{6}=3 \

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