Ответ Автор - qoolebyaqa (x+1)^(1/6) = tt^2-3t+2=0D=1t1=2 t2=1(x+1)^(1/6) = 1x+1 = 1 x1=0 (x+1)^(1/6) = 2x+1 = 2^6x+1=64x2=63