Автор - tteslyyaa
log(a^k) b^n = n/k * log(a) b
a^log(a) b = b
lg = log(10)
a^m/a^n = a^(m-n)
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log(5) 1/125 = log(5) 1/5^3 = log(5) 5^-3 = -3
log(1/2) 1/8 = log(1/2) (1/2)^3 = 3
lg 100 = lg 10^2 = 2
lg 0.001 = lg 1/1000 = lg 1/10^3 = lg 10^-3 = -3
4^(1/2 - log(2) √3) = 2^2(1/2 - log(2) √3) = 2^(1 - 2log(2) √3) = 2/2^log(2) (√3)² = 2/3
(или 2^(1 - 2log(2)√3) = 2^(log(2) 2 - log(2) √3²) = 2^log(2) 2/3 = 2/3)