Автор - timadavletov2005

Найдите значение выражения:
1) (0.8^-2 + 0.6^-2)^-1
2)(5*2^-2 - 20*5^-2) : (4/3)^-2

Ответ

Автор - zinaidazina

1.

(0,8^{-2}+0,6^{-2})^{-1}=((frac{8}{10})^{-2}+(frac{6}{10})^{-2})^{-1}=

=((frac{4}{5})^{-2}+(frac{3}{5})^{-2})^{-1}=((frac{5}{4})^{2}+(frac{5}{3})^{2})^{-1}=

=(frac{25}{16}+frac{25}{9})^{-1}=(frac{25*9+25*16}{16*9})^{-1}=

=(frac{25*(9+16)}{16*9})^{-1}=(frac{25*25)}{16*9})^{-1}=

=(frac{625}{144})^{-1}=(frac{144}{625})^{1}=frac{144}{625}

2.

(5*2^{-2}-20*5^{-2}):(frac{4}{3})^{-2}=(5*(frac{1}{2})^2-20*(frac{1}{5})^2):(frac{3}{4})^2=

=(5*frac{1}{4}-20*frac{1}{25}):frac{9}{16}=

=(frac{5}{4}-frac{20}{25}):frac{9}{16}=

=(frac{5}{4}-frac{4}{5})*frac{16}{9}=(frac{5*5}{4*5}-frac{4*4}{5*4})*frac{16}{9}=

=(frac{25}{20}-frac{16}{20})*frac{16}{9}=(frac{25}{20}-frac{16}{20})*frac{16}{9}=

=frac{9}{20}*frac{16}{9}=frac{4}{5}=0,8

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