Автор - jekarehtin

1) tgx=1 2)tgx=-1 3)tgx=0 4)tgx=-2 5)tg^2x-6tgx+5=0 6)tg^2x-2tgx-3=0

Ответ

Проверено экспертом

Автор - nKrynka
1) tgx = 1
x = π/4 + πn, n∈Z
2) tgx = - 1
x = - π/4 + πn, n∈Z
3) tgx = 0
x = πk, k∈Z
4) tgx = - 2
x = arctg(-2) + πk, k∈Z
x = -arctg(2) + πk, k∈z
5)  tg^2x - 6tgx + 5 = 0
a)  tgx = 1
x1 = π/4 + πn, n∈Z
b)  tgx = 5
x2 = arctg(5) + πk, k∈z
6)  tg^2x - 2tgx - 3 = 0
a)  tgx = - 1
x1 = - π/4 + πn, n∈Z
b)  tgx = 3
x2 = arctg(3) + πk, k∈z

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