Автор - modnik968

найдите корень уравнения 1)(х-7)^2-49=0 2)(6+у)^2-81=0 3) 100-(z-19)^2=0 4) 25-(13+t)^2=0 ​

Ответ

Автор - bobyy13
1) 2х-14-49=0
2х=63
х=31.5
2)12+2у-81=0
2у=69
у=34.5
3) 100-19z+38=0
-19z=-138

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