Автор - iakrut228

1/х+7+1/х-3=0
Найдите корень уравнения.

Ответ

Автор - and4666

 frac{x - 3 + x + 7} {(x + 7)(x - 3)} = 0 \  frac{2x + 4}{(x  + 7)(x - 3)}  = 0 \ x =  - 7 \ x = 3  \ 2x + 4 = 0 \ x =  - 2

[tex] frac{x - 3 + x + 7} {(x + 7)(x - 3)} = 0 \  frac{2x + 4}{(x  + 7)(x - 3)}  = 0 \ x =  - 7 \ x = 3  \ 2x + 4 = 0 \ x =  - 2[/tex]

Ответ

Автор - ooooooo9

1/х+7+1/х-3=0

х-3+х7

_______= 0 это дробь

(х+7)(х+3)

2х+4

-----------------------=0

(x + 7)(x - 3) \ x =  - 7 \ x = 3 \ \  2x + 4 = 0

2х+4=0

х=-2

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