Автор - kristina92164

сумма нулей функции у=(х-1/√3+√2)(х-√3-√2) равна​

Ответ

Автор - WhatYouNeed

y=(x-(1/sqrt{3}-sqrt{2}))(x-(sqrt{3}+sqrt{2}))\1/sqrt{3}+sqrt{3}\frac{4sqrt{3} }{3}

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