Автор - anjuta5858

срочно пожалуйста!!!!!!!

Ответ

Автор - larisakravcenko

Ответ:

Пошаговое объяснение:

1) (tg(180° - α) · cos(180° - α) · tg(90° - α)) : (sin(90° + α) · ctg(90° - α) · tg(90° + α)) = ( - tgα · ( - cosα) · ctgα) : (cosα · tgα · ( - ctgα)) = - (tgα · cosα · ctgα) : (cosα · tgα · ctgα) = - 1

2) sinπ/6 + 3cosπ/2 - 3ctgπ/4 + 4tg0° = 1/2 + 3 · 0 - 3 · 1 + 4 · 0 =

= 0,5 - 3 = - 2,5

3) cos²(π + α) - cos( α + 3π/2) · sin(2π - α) + tg²(π - α) = cos²α - sinα · ( - sinα) + tg²α =  cos²α + sin²α + tg²α = 1 +  tg²α = 1/ cos²α

4) cos327° - cos343° - cos( - 753°) + sin220° + cos( - 377°) - sin( - 40°) =

= cos(360° - 33°) - cos(360° - 17°) - cos(720° + 33°) + sin(180° + 40°) + cos(360° + 17°) + sin40° =

= cos33° - cos17° - cos33°- sin40° + cos17° + sin40° = 0  

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