Автор - kuroky02

2sin pi/3×cos pi/6-1/2tg^2pi/3

Ответ

Автор - sangers

Ответ:


Пошаговое объяснение:

2*sin(π/3)*cos(π/6)-(1/2)*tg²(π/3)=2*√3/2*√3/2-(1/2)*(√3)²=3/2-3/2=0.

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