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Автор - GoodGroove

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Ответ

Автор - Lindemann94

intlimits{sin(5x-2)} , dx \intlimits{frac{sin(t)}{5}} , dt\frac{1}{5}*intlimits{sin(t)} , dt\frac{1}{5}*(-cos(t)) \frac{1}{5}*(-cos(5x-2))\-frac{cos(5x-2)}{5} \-frac{cos(5x-2)}{5} + C

C∈R

intlimits{(x+5)cos(x)} , dx \intlimits{x*cos(x)+5cos(x)} , dx\intlimits{x*cos(x)} , dx + intlimits{5cos(x)} , dx\ x*sin(x)+cos(x)+5sin(x)\ x*sin(x)+cos(x)+5sin(x) +C

C∈R

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