Автор - dilnaz5131

Помогите пожалуйста,обведённые номераplease help

Ответ

Автор - maymr
Здравствуйте!

1)
 frac{1}{24} x - ( frac{1}{3} x + ( -  frac{2}{9} x - ( -  frac{4}{9} x + ( -  frac{5}{12} x)))) =  \  \  =  frac{1}{24} x - ( frac{1}{3} x + ( -  frac{2}{9} x - ( -   frac{16}{36} x  -  frac{15}{36} x))) =  \  \  =  frac{1}{24} x - ( frac{1}{3} x + ( -  frac{8}{36} x  +  frac{31}{36} x)) =  \  \  frac{1}{24} x - ( frac{12}{36} x +  frac{23}{36} x) =  \  \  =  frac{1}{24} x -  frac{35}{36} x =  \  \  =  frac{3}{72} x -  frac{70}{72} x =  \  \  =   - frac{67}{72} x

2)
8.4 - 2.7(7b - 1.3(10 - 11b)) - 15.7b =  \   = 8.4 - 2.7(7b - 13 + 14.3b) - 15.7b =  \  = 8.4 - 18.9b + 35.1 - 38.61b - 15.7b =  \  = 43.5 - 73.21b
3)
 -  frac{3}{40} ( - 2a - ( frac{1}{3}  + 12y)) -  frac{1}{7} ( - 14a - (7 +  frac{2}{3} a)) =  \  \  =  -  frac{3}{40} ( - 2a -  frac{1}{3}  - 12y) -  frac{1}{7} ( - 14a - 7 -  frac{2}{3} a) =  \  \  =  frac{3}{20} a +  frac{1}{40}  + 0.9y  + 2a + 1 +  frac{2}{21} a=  \  \  = 2 frac{103}{420} a + 1.025 +  0.9y

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