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Rechnung
n(n+10)-28=2(n+10)\n^2+10n-28=2n-20\n^2+10n-2n-28+20=0\n^2+8n-8=0\D=8^2-4*1*(-8)=64+32=100\n_1= frac{-8+10}{2}=1\n_2=frac{-8-10}{2}=-9<0\\n=1\n+10=1+10=11

Ответ: 1 и 11

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