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mathgenius

Ответ:

x=π/2 +π*n  n∈Z

x=arcctg(-3)+π*k  k∈Z

Пошаговое объяснение:

Это   уравнение эквивалентно:

2cos^2(x)=-3sin(2x)

cos(x)*(cos(x) +3*sin(x))=0

1) cos(x)=0

   x=π/2  +π*n  n∈Z

2)  cos(x)=-3*sin(x)   ( sin(x)≠0 ,тк  тогда в  этом случае сosx=+-1 , а +-1≠0)

     Тогда  можно поделить  обе части на sin(x)

     ctg(x)=-3

      x=arcctg(-3)+π*k  k∈Z

   

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