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Bena20191

Ответ:

Пошаговое объяснение:

а) y=x^5+x^3+x

y'=5x⁴+3x²+1

б)y=(5x+2)^(-3)


y'=-3(5x+2)⁻³⁻¹=-3(5x+2)⁻⁴=-3/(5x+2)⁴

в) непонятно что в числителе, на всякий случай 2 варианта

в-1) y=(sinx-cosx)/x

y'  = ((sinx-cosx)'x-(sinx-cosx)x')/x²=((cosx+sinx)x-sinx+cosx)/x²=

(xcosx+xsinx-sinx+cosx)/x²

в-2) y=sinx-((cosx)/x)

y'  = cosx-((cosx)'x-(cosx)x')/x²=cosx-(-(sinx)'x-cosx))/x²=cosx+(xsinx+cosx)/x²

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