Автор - kseunka

(1/4-0,7*2/4)*4
(1/7-0,9*2/9)*7
-2ав+3(4а+в)²= при а√7,в=√3
помогите,пожалуйста.​

Ответ

Автор - danielochka16

1)

( frac{1}{4}  -  frac{7}{10}  times  frac{1}{2} ) times 4  = ( frac{1}{4}  -  frac{7}{20} ) times 4 =  -  frac{1}{10}  times 4

2)

( frac{1}{7}  -  frac{9}{10}  times  frac{2}{9} ) times 7 = ( frac{1}{7}  -  frac{1}{5} ) times 7 =  -  frac{2}{35}  times 7 =  -  frac{2}{5}

3)

 =  - 2 sqrt{21}  + 345 + 24 sqrt{21}  = 22 sqrt{21}  + 345

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