Автор - rem40

Срочно!!! Решите подробно! Даю 35 баллов!

Ответ

Автор - Alexei78

дано

n(CL2) = 2 mol

----------------------

V(HCL)-?

H2+CL2-->2HCL

n(CL2) = 2n(HCL)

n(HCL)= 2*2 = 4  mol

V(HCL) = Vm*n = 22.4 * 4 = 89.6 L

ответ 89.6 л

4)

дано

m(CaO) = 56 g

--------------------

m(Ca)-?

V(O2)-?

2Ca+O2-->2CaO

M(CaO) = 56 g/mol

n(CaO) = m/M= 56 / 56 = 1 mol

2n(Ca) = 2n(CaO) = 1 mol

n(Ca) = 1 moL

M(Ca) = 40 g/mol

m(Ca) = n*M = 1*40 = 40 g

n(O2) = 2n(CaO)

n(O2) = 1/2 = 0.5 mol

V(O2) = Vm*n = 22.4 * 0.5 = 11.2 L

ответ 40 г., 11.2 л

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