Автор - mamekolisa

Помогите, пожалуйста, решить.

Ответ

Автор - michindjeva

 frac{ sqrt[3]{ {(22 {a}^{2} )}^{6} } }{ {a}^{4} }  =   frac{ {(22 {a}^{2} )}^{2} }{ {a}^{4} }  =  frac{484 {a}^{4} }{ {a}^{4} }  = 484
 {(36a)}^{1.5}  =  {(36a)}^{ frac{15}{10} }  =  {(36a)}^{ frac{3}{2} }  =  \  sqrt{ {(36a)}^{3} }  \ a sqrt{a}  =  sqrt{ {a}^{3 } }  \  frac{ sqrt{ {36}^{3}  times  {a}^{3} } }{ sqrt{ {a}^{3} } }  = 218
 {5}^{3x + 1}  div  {125}^{x }  div x =  \  {5}^{3x + 1}  div  {( {5}^{3} )}^{x}  div  times  \ 3x + 1 - 3x = 1 \  {5}^{1}  div  frac{1}{13}  = 5 times 13 = 65

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