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Автор - Zaness

СРОЧНО
Найдите выталкивающую силу, действующую на брусок размером 9 м3 , на треть объёма погружённый в спирт.

Ответ

Автор - kopnevmaxim

F Архимеда = po * V * g= 800 * 3* 10= 24000 (Н) = 24(кН)

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