Ответ Автор - армения20171 √а+√b=5;a*b=4(√a+√b)³=5³√a³+3a√b+3b√a+√b³=125a√a+b√b=125-3(a√b+b√a)=125-3(5a-a√a+5b-b√b)-2a√a-2b√b=125-5(a+b)=-2(a√a+b√b)=125-5*21=20a√a+b√b=-10(√a+√b)²=25a+b=21√a+√b=5a√a+a√b=5aa√b=5a-a√ab√a+b√b=5bb√a=5b-b√ba√a+b√b=-10