Ответ Автор - gulsezimmuginova sin(3x+π/6)=-√3/23x+π/6= -π/3+2πn3x= - π/3 - π/6 + 2πn3x= - 3π/6 + 2πn3x= -π/2 +2πnx= -π/6 + 2πn/3