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Ответ

Ответ дан
alex080297

m1(р-ра)=500 гр

m1соли=W1*m1=0.4*500=200гр -содержит 1 раствор

m1 H2O=500-200=300 гр - содержит 1 раствор

m2 воды = 300+200=500 гр воды

m2 (р-ра)=m2 воды+ m1 соли = 500+200=700 гр

W2 = 200/700=0.286

Ответ:0,286

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