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Ответ дан
uzganj2607

5/x^2-4+x/2-x=2x/x+2

5/x^2-4+x(2+x)/(2-x)(2+x)=2x(x-2)/(x+2)(x-2)

5/x^2-4-x(2+x)/(x+2)(x-2)=2x(x-2)/(x+2)(x-2)

(5-2x-x^2-2x^2+4x)/(x^2-4)=0

-3x^2+2x+5=0

D=4+4*3*5=64=8^2

X1=(-2+8)/(-6)=6/(-6)=-1

X2=(-2-8)/-6=(-10)/(-6)=5/3

Ответ: x1=-1 x2=5/3

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