Автор - mana23

1) Найдите 24cos2a,если sina= -0,2

Ответ

Автор - ЮлЯшКа123454321

cos(2a) = cos²(a) - sin²(a) = 1 - 2sin²(a)

24cos(2a) = 24·(1 - 2sin²(a)) = 24·(1 - 2·(-0,2)²) = 24·(1-0,04) = 24·0,96 = 23,04

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